allow

[sth; sth to be sth; sb to do sth; see also: enable, permit, possible]

These theorems allow one to guess the Plancherel formula. [Or: allow us to guess; not: “allow to guess”]

As the space of Example 3 shows, complete regularity of $X$ is not enough to allow us to do that.

This allows proving the representation formula without having to integrate over $X$.

This easily allows the cases $c=1,2,4$ to be solved.

By allowing $f$ to have both positive and negative coefficients, we obtain ......

It is therefore natural to allow (5) to fail when $x$ is not a continuity point of $F$.

The limit always exists (we allow it to take the value $\infty$).

Lebesgue discovered that a satisfactory theory of integration results if the sets $E_i$ are allowed to belong to a larger class of subsets of the line.

In [3] we only allowed weight functions that were $C^1$.

It should be possible to enhance the above theorem further by allowing an arbitrary locally compact group $L$.

Here we allow $a=0$.

We deliberately allow that a given $B$ may reappear in many different branches of the tree.



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