## Mathematical English Usage - a Dictionary

## as

[*see also*: like, since]

If $f$ is as in (8), then ...... [*Not*: “like in (8)”]

We can multiply two elements of $E$ by concatenating paths, much as in the definition of the fundamental group.

......, where each function $g$ is as specified $\langle$described$\rangle$ above.

Actually, [3, Theorem 2] does not apply exactly as stated, but its proof does.

They were defined directly by Lax [2], essentially as we have defined them.

For $k=2$ the count remains as is.

In the case where $A$ is commutative, as it will be in most of this paper, we have ......

As a first step we identify the image of $\Delta$.

Then $F$ has $T$ as its natural boundary.

The algorithm returns 0 as its answer.

Now $X$ can be taken as coordinate variable on $M$.

If one thinks of $x, y$ as space variables and of $z$ as time, then ......

Then $G$ is a group with composition as group operation.

We have $A\equiv B$ as right modules.

Then $E$ is irreducible as an $L$-module.

......, as is easily verified.

......, as noted $\langle$as was noted$\rangle$ in Section 2. [*Not*: “as it was noted”]

......, as desired $\langle$claimed/required$\rangle$.

The elements of $F$ are not in $S$, as they are in the proof of ......

Note that $F$ is only nonnegative rather than strictly positive, as one may have expected.

Then $G$ has 10 normal subgroups and as many non-normal ones.

Moreover, $H$ is a free $R$-module on as many generators as there are path components of $X$.

But $A$ has three times as many elements as $B$ has.

We can assume that $p$ is as close to $q$ as is necessary for the following proof to work.

Then $F$ can be as great as 16.

Each tree is about two-thirds as deep as it was before.

As $M$ is ordered, we have no difficulty in assigning a meaning to $(a,b)$.

The ordered pair $(a,b)$ can be chosen in 16 ways so as not to be a multiple of $(c,d)$.

Now (3) is clear. As for (4), it is an immediate consequence of Lemma 6. [= Concerning (4)]

As with the digit sums, we can use alternating digit sums to prove ...... [= Just as in the case of digit sums]

Go to the list of words starting with: a
b
c
d
e
f
g
h
i
j
k
l
m
n
o
p
q
r
s
t
u
v
w
y
z