[to/with sth; see also: difference, oppose]
Note that, in contrast to $F$, the function $G$ is bounded. [Not: “contrary to $F$”]
In contrast, Theorem 2 shows that ......
By contrast, $T$ does not have this symmetry.
This is in marked contrast to the behaviour of orthonormal sets in a Hilbert space.
Note the contrast with Theorem 3.
[with sth; see also: differ]
This contrasts sharply with the situation in metrizable spaces.
This contrasts with (but does not contradict) Theorem 2 of [6].
We shall see that the two cases where $A=1$ and where $B=2$ give contrasting conclusions.
Go to the list of words starting with: a
b
c
d
e
f
g
h
i
j
k
l
m
n
o
p
q
r
s
t
u
v
w
y
z