contribution

[from sth; to sth]

This decrease is offset by the contribution from the poles.

Thus we may count the contribution to the periodic points from each prime separately.

We shall thus avoid doubly counting the same contribution.

Note that $A_n$ makes only a contribution of at most $N^2$.

Clearly, the contribution from those $r$ with $A(r)>0$ can be neglected.

However, we prefer to avoid this issue altogether by neglecting the contribution of $B$ to $S$.

If nothing else, I hope to convince my readers that Segal's theorem deserves recognition as a profound contribution to Gaussian analysis.



Go to the list of words starting with: a b c d e f g h i j k l m n o p q r s t u v w y z