The remarks following Theorem 2 show that $a=0$.
The analysis to follow only covers the case $d=1$.
We make the following provisional definition, which is neither general nor particularly elegant, but is convenient for the induction which is to follow.
The following three statements are equivalent: ......
For $D$ a smooth domain, the following are equivalent.
The following has an almost identical proof to that of Lemma 2.
The idea of the ensuing computations is the following: ......
His argument is as follows.
The fact that the number $T(p)$ is uniquely defined, even though $p$ is not, enables us to define the nullity of $A$ as follows.
In what follows $\langle$In all that follows$\rangle$, $L$ stands for ......
Throughout what follows, we shall freely use without explicit mention the elementary fact that ......
It follows that $a$ is positive. [= Hence $\langle$Consequently,/Therefore,$\rangle$ $a$ is positive.]
Firstly, if $G$ is abelian, does it follow that $S(G) = K$, or equivalently, that $X_G = p(M(G))$?
If we prove that $G>0$, the assertion follows.
The general case follows by changing $x$ to $x-a$.
We follow Kato  in assuming $f$ to be upper semicontinuous.
Following the same lines we find that it takes $k$ prolongations to get an immersed curve.
The proof follows very closely the proof of (2), except for the appearance of the factor $x^2$.
It is intuitively clear that the amount by which $S_n$ exceeds zero should follow the exponential distribution.