[see also: few]
Then $F$ is 2 less than $G$.
Let $A_n$ be a sequence of positive integers none of which is 1 less than a power of two.
Thus $F$ is less than or equal to $G$. [Not: “less or equal to $G$”, nor “less than or equal $G$”]
Here $F$ is strictly less than $G$.
Thus $F$ is no less than $G$.
Clearly, $F$ is less than 1 in absolute value.
Less than 1 in $p$ of its points will result in a quartic with ideal class number $p$.
[Do not write: “$X$ has no less elements than $Y$ has” if you mean: $X$ has no fewer elements than $Y$ has; less should not be followed by a plural countable noun. However, use less when it is followed by than or when it appears after a noun: $X$ has no less than twenty elements; $Y$ has ten elements or less.]
Much less is known about hyperbolically convex functions.
Although our proof is a little tedious, it is much less so than Ito's original proof, which was carried out without the benefit of martingale technology.
This method is recently less and less used.
to $\langle$in$\rangle$ a lesser degree