[*see also*: few]

Then $F$ is 2 less than $G$.

Let $A_n$ be a sequence of positive integers none of which is 1 less than a power of two.

Thus $F$ is less than or equal to $G$. [*Not*: “less or equal to $G$”, nor “less than or equal $G$”]

Here $F$ is strictly less than $G$.

Thus $F$ is no less than $G$.

Clearly, $F$ is less than 1 in absolute value.

Less than 1 in $p$ of its points will result in a quartic with ideal class number $p$.

[Do not write: “$X$ has no less elements than $Y$ has” if you mean: * $X$ has no fewer elements than $Y$ has*; * less* should not be followed by a plural countable noun. However, use * less* when it is followed by * than* or when it appears after a noun: $X$ has no less than twenty elements; $Y$ has ten elements or less.]

Much less is known about hyperbolically convex functions.

Although our proof is a little tedious, it is much less so than Ito's original proof, which was carried out without the benefit of martingale technology.

This method is recently less and less used.

to $\langle$in$\rangle$ a lesser degree

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