## not

For $m$ not an integer, the norm can be defined by interpolation.

For $f$ not in $B$, ......

However, $M$ is generally not a manifold.

It is not generally possible to restrict $f$ to the class $D$.

We note that $H$ is in fact not monotone if this condition is violated.

[Do not use not to negate an adjective placed before a noun. Write: a non-monotone function, and not: “a not monotone function”.]

Is there a relation between $A$ and $B$? There certainly is not if ......

Now $f$ is independent of the choice of $\gamma$ (although the integral itself is not).

Examples 1 and 2 give two operators, the former bounded and the latter not, with ......

Let us stress that $c$ is a term and not a subset of $C$.

Obviously, $S$ may be $P$, but it may also not be $P$.

The result above seems not to be a consequence of previous results.

The ordered pair $(a,b)$ can be chosen in 16 ways so as not to be a multiple of $(c,d)$.

Why not increase the precision of these statements?

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