[see also: converse, opposite]
in reverse order
the reverse inequality $\langle$inclusion$\rangle$
We show that ...... by reverse induction on $i$, starting at $i=n$ and working down to $i=0$.
None of these implications can be reversed.
By reversing the steps above, we see that ......
One is tempted to reverse the order of integrations but that is illegitimate here.
with the order of $a$ and $b$ reversed
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