Mathematical English Usage - a Dictionary

by Jerzy Trzeciak

weak

The convergence of the sum on the left is of course a weaker statement than the convergence of (2).

In fact, we shall prove our result under the weaker hypothesis that $W$ is weakly bounded, rather than just bounded, on an infinite subset of $G$.

The weight satisfies a weak type $(1,1)$ estimate.

Then $x_n$ converges weak$^*$ to $x$.



Go to the list of words starting with: a b c d e f g h i j k l m n o p q r s t u v w y z