well

[see also: also, too]

For binary strings, the algorithm does not do quite as well.

But $H$ itself can equally well be a member of $S$.

Our asymptotic results compare reasonably well with the numerical results reported in [8].

Since the integrands vanish at 0, we may as well assume that ......

Other types fit into this pattern as well.

Note that both sides of the inequality may well be infinite.

A cycle may very well be represented as a sum of paths that are not closed.

It may well be that no optimal time exists, as the following example shows.

Although standard, the notion of a virtual vector bundle is not particularly well known.



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