[see also: that]
For which $f$ does equality hold in this inequality?
There has since been a series of improvements, of which we briefly mention the work of Levinson.
Where there is a choice of several acceptable forms, that form is selected which ......
Let $I$ be the family of all subalgebras which contain $F$. [Or: that contain $F$; you can use either that or which in defining clauses.]
We denote the complement of $A$ by $A^c$ whenever it is clear from the context with respect to which larger set the complement is taken.
The map $f$, which we know to be bounded, is also right-continuous. [Not: “that we know”; do not use that in non-defining clauses.]
Hence $F$ is compact, which yields $M=N$. [Not: “what yields”]
......, which completes the proof.
[Note the difference between what and which in sentences similar to the last two examples: what refers to what follows it, while which refers to what precedes it.]
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