[from sth; amer. than sth; see also: distinct, other, various, several, particular, disparate]
The case $a=1$ requires a different approach.
The situation is quite different if we replace $H(U)$ by certain subclasses.
by using a somewhat different method
This idea is very little different from what can already be found in [2].
Our solution is completely different from theirs. [Not: “much different”]
There is another, entirely different, way to see that $A=B$. Namely, one can first show that ......
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