Neither (1) nor (2) alone is sufficient for (3) to hold.

Thus $A$ is neither symmetric nor positive.

Both $X$ and $Y$ are countable, but neither is finite.

Neither of them is finite.

[Use neither when there are two alternatives; if there are more, use none.]

Let $u$ and $v$ be two distributions neither of which has compact support.

As shown in Figure 3, neither curve intersects $X$.

In neither case can $f$ be smooth. [Note the inversion after the negative clause.]

Both proofs are easy, so we give neither.

Thus $X$ is not finite; neither $\langle$nor$\rangle$ is $Y$.

Neither is the problem simplified by assuming $f=g$.

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