[see also: alone, just, merely, single, solely]
Assume that the only functions $v$, $w$ satisfying (2) are $v=w=0$.
Then the one and only integral curve of $L$ starting from $x$ is the straight line $l$.
Here $\{x\}$ is the set whose only member is $x$.
The problem is to move all the discs to the third peg by moving only one at a time.
However, only five of these are distinct.
Note that $F$ is defined only up to an additive constant.
We need only consider the case ...... [Or: We only need to consider]
The proof will only be indicated briefly.
We have to change the proof of Lemma 3 only slightly.
To prove (8), it only remains to verify that ......
Thus $X$ assumes the values 0 and 1 only.
Only for $x=1$ does the limit exist. [Note the inversion.]
If we know a covering space $E$ of $X$ then not only do we know that ...... but we can also recover $X$ (up to homeomorphism) as $E/G$.
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