only

[see also: alone, just, merely, single, solely]

Assume that the only functions $v$, $w$ satisfying (2) are $v=w=0$.

Then the one and only integral curve of $L$ starting from $x$ is the straight line $l$.

Here $\{x\}$ is the set whose only member is $x$.

The problem is to move all the discs to the third peg by moving only one at a time.

However, only five of these are distinct.

Note that $F$ is defined only up to an additive constant.

We need only consider the case ...... [Or: We only need to consider]

The proof will only be indicated briefly.

We have to change the proof of Lemma 3 only slightly.

To prove (8), it only remains to verify that ......

Thus $X$ assumes the values 0 and 1 only.

Only for $x=1$ does the limit exist. [Note the inversion.]

If we know a covering space $E$ of $X$ then not only do we know that ...... but we can also recover $X$ (up to homeomorphism) as $E/G$.



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